4x^2-4^8=0

Solution for 4x^2-4^8=0 equation:

4x^2-4^8=0

We add all the numbers together, and all the variables

4x^2-65536=0

a = 4; b = 0; c = -65536;
Δ = b2-4ac
Δ = 02-4·4·(-65536)
Δ = 1048576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1048576}=1024$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1024}{2*4}=\frac{-1024}{8}
=-128
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1024}{2*4}=\frac{1024}{8}
=128
$